Здравейте! Някой може ли да ми сложи воден знак на тоя код?
uploadconf.php
upload.php
uploadconf.php
Код:
<?php
$upload_dir = "users/". filter($_SESSION['username']) . "/gallery/";
$uploaded_dir = "users/". filter($_GET['username']) . "/gallery/";
$upload_avatarsdir = "avatars/";
$size_bytes = 7340032;
$extlimit = "yes";
$limitedext = array(".gif",".jpg",".png",".jpeg",".bmp");
?>
Код:
<?php
if($_POST['submit'])
{
include("./include/conf.php");
include("./include/uploadconf.php");
if (is_dir($upload_avatarsdir)) {
$file_tmp = $_FILES['myfile']['tmp_name'];
$file_name = $_FILES['myfile']['name'];
$file_size = $_FILES['myfile']['size'];
if (!is_uploaded_file($file_tmp)){
exit;
}
$ext = strrchr($file_name,'.');
if (($extlimit == "yes") && (!in_array(strtolower($ext),$limitedext))) {
exit;
}
if ($file_size > $size_bytes){
exit;
}
$file_name = str_replace(' ', '_', $_SESSION['username'] . $ext);
$res = 0;
if (move_uploaded_file($file_tmp,$upload_avatarsdir.$_SESSION['username'] . $ext)) {
$query = "UPDATE `users` SET `avatar` = '" . $upload_avatarsdir.$_SESSION['username'] . $ext . "' WHERE `username` = '$_SESSION[username]'";
$result = mysql_query($query);
$res = 1;
sleep(1);
?>
<script language="javascript" type="text/javascript">window.top.window.stopUpload(<?php echo $res; ?>);</script>
<?php
}
}
}