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NewGuy каза:$query = "SELECT id,image,cat FROM galeria " . "WHERE cat=`1` LIMIT $redove, $broinastranica";
Къде е грешката в заявката? Немога да си намеря грешката. :roll:
Пак дава грешка Error, query failed :roll:animatora каза:$query = "SELECT id,image,cat FROM galeria WHERE cat=`1` " . "LIMIT $redove, $broinastranica";
Parse error: syntax error, unexpected T_LNUMBER in C:\Program Files\xampp\htdocs\mania\proekti.php on line 22animatora каза:$query = "SELECT * FROM galeria WHERE cat="1 " . "LIMIT $redove, $broinastranica";
animatora каза:$query = "SELECT id,image,cat FROM galeria WHERE cat=`1` " . "LIMIT $redove, $broinastranica";
$query = "SELECT * FROM `files` WHERE vid = 'Литература'" . " LIMIT $redove, $broinastranica";
animatora каза:$query = "SELECT * FROM galeria WHERE cat="1 " . "LIMIT $redove, $broinastranica";
дай целия код мое др да е грешката
<?php
$user="root"; //user на базата данни
$password=""; //pass на базата данни
$database="kartinki"; //име на базата данни
mysql_connect(localhost,$user,$password);
mysql_select_db($database) or die( "Unable to select database");
$broinastranica = 20;
$pageNum = 1;
if(isset($_GET['page']))
{
$pageNum = $_GET['page'];
}
$redove = ($pageNum - 1) * $broinastranica;
//заявката ще върне само посочените редове - примерно от 20 до 40 в зависимост от $_GET['page']
$query = "SELECT * FROM galeria" . "WHERE cat=`1` LIMIT $redove, $broinastranica";
$result = mysql_query($query) or die('Error, query failed');
echo "<table border=1>";
// print-ваме посочените редове в таблица.
while($row = mysql_fetch_array($result))
{
echo '<tr><td>'.$row['id'].'</td><td>'.$row['image'].'</td><td>'.$row['cat'].'</td></tr>';
}
echo"</table>";
$query = "SELECT COUNT(zag) AS numrows FROM statia";
$result = mysql_query($query) or die('Error, query failed');
$row = mysql_fetch_array($result, MYSQL_ASSOC);
$numrows = $row['numrows'];
$maxPage = ceil($numrows/$broinastranica);
$self = $_SERVER['PHP_SELF'];
$nomeranastranici = '';
for($page = 1; $page <= $maxPage; $page++)
{
if ($page == $pageNum)
{
$nomeranastranici .= " $page ";
}
else
{
$nomeranastranici .= " <a href="$self?page=$page">$page</a> ";
}
}
if ($pageNum > 1)
{
$page = $pageNum - 1;
$predishna = " <a href="$self?page=$page"> [<<<<<] </a> ";
$parva = " <a href="$self?page=1">[първа]</a> ";
}
else
{
$predishna = ' ';
$parva = ' ';
}
if ($pageNum < $maxPage)
{
$page = $pageNum + 1;
$sledvashta = " <a href="$self?page=$page"> [>>>>>] </a> ";
$posledna = " <a href="$self?page=$maxPage">[последна]</a> ";
}
else
{
$sledvashta = ' ';
$posledna = ' ';
}
echo $parva . $predishna . $nomeranastranici . $sledvashta . $posledna;
?>
NewGuy каза:$query = "SELECT id,image,cat FROM galeria WHERE cat=`1` LIMIT $redove, $broinastranica";