Lambenstein
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Някой може ли да ми каже как кода по-долу да направя да ми изкарва bbcode-а от този скрипт
Благодаря предварително
Код:
<?php
include "config.php";
$id = $_GET['id'];
$db = mysql_query("SELECT * FROM blognews WHERE id='$id'")or die (mysql_error());
$i = 0; // prisvoqvame na $i stoinost 0
while($row = mysql_fetch_assoc($db))
{
$resultat = mysql_num_rows($query);
$name = $row['name'];
$text = $row['text'];
$snimka = $row['snimka'];
$website = $row['website'];
$ka4il = $row['ka4il'];
if($i%1 == 0)
{
echo "
<article class='single-post'>
<header>
<h3 class='style1 style2'>$row[name]</h3>
</header>
<div class='featured-thumbnail no-hover'><div class='img-wrap'><img width='584' height='296' src='admin/images/blogposts/$row[snimka]' class='attachment-post-thumbnail wp-post-image' alt='$row[name]' title='$row[name]' /></div></div> <div class='post-content'>
<p>$row[text]</p>
</div>
</article>
<div id='post-author'>
";
$db2 = mysql_query("SELECT * FROM users WHERE username = '$ka4il'") or die (mysql_error());
$db2 = mysql_fetch_array($db2);
{
echo"
<h3>Written by $db2[username]</h3>
<p class='gravatar'><img alt='$db2[username]' src='admin/images/avatars/$db2[avatar]' class='avatar avatar-80 photo' height='80' width='80' /></p>
<div id='author-description'>
$db2[info]
<div id='author-link'>
</div>
</div>
</div>";
}
}
$i++;
}
?>
Благодаря предварително