Здравейте, нещо не мога да си намеря грешката...
Parse error: syntax error, unexpected $end in /www/buldom.net/www/root/realestate/estates.php on line 81
Parse error: syntax error, unexpected $end in /www/buldom.net/www/root/realestate/estates.php on line 81
Код:
<?php include("header.php"); ?>
<style type="text/css">
table.sample {
border-width: 1px;
margin-left:5px;
margin-bottom:5px;
float:left;
border-spacing: 2px;
border-style: outset;
border-color: gray;
border-collapse: separate;
background-color: rgb(255, 255, 240);
}
table.sample th {
border-width: 1px;
padding: 1px;
border-style: hidden;
border-color: gray;
background-color: rgb(250, 240, 230);
-moz-border-radius: ;
}
table.sample td {
border-width: 1px;
padding: 1px;
border-style: hidden;
border-color: gray;
background-color: rgb(250, 240, 230);
-moz-border-radius: ;
}
</style>
<div class="latest_properties">
Преглед по категории :<br /> |
<?php
$gener = $_GET['gener'];
$cat = mysql_query("SELECT * FROM `imoti_cat`");
while($row = mysql_fetch_array($cat)){
$our = mysql_query("SELECT count(id) as total FROM imoti WHERE cat=$row[id]");
while($raw=mysql_fetch_array($our)){
$total=$raw['total'];
}
echo "<span><a href=\"?gener=$row[id]\">$row[value]</a></span> | ";
}
?>
<br /></div>
<br />
<?php if($gener == ""){
echo "Преглед по категории";
} else {
$cat = mysql_query("SELECT * FROM `imoti_cat` WHERE `id`='$gener'");
$category = mysql_fetch_array($cat);
$id=$category['id'];
$genername = $category['value'];
echo "<font size='3'>Имоти в категория $genername</font><br />";
}
?>
<hr />
<?php
if($_GET['gener']){
$table = "imoti";
$total = mysql_result(mysql_query("SELECT COUNT(*) FROM $table"),0);
$query = "SELECT * FROM `$table` WHERE `cat`='$gener' ORDER BY `id` DESC LIMIT $limitvalue, $pp";
$result = mysql_query($query);
while($row=mysql_fetch_array($result))
?>
<table class="sample" width="150" border="2">
<td><a href="view.php?id=<?php echo $row[id]; ?>"><img src="thumb.php?w=150&img=imoti/<?php echo $row[snimka1]; ?>"></a></td>
<tr>
<td><a href="view.php?id=<?php echo $row[id]; ?>" onmouseover="tooltip.show('<img src=\'thumb.php?w=250&img=imoti/<?php echo $row[snimka1]; ?>\' width=\'250\' hight=\'250\'>');" onmouseout="tooltip.hide();"><?php echo $row[ime]; ?></a></td>
</tr>
<tr>
<td><?php echo $row[cena]; ?></td>
</tr>
</table>
<?php include("footer.php"); ?>