"Кой е онлайн в сайтa" да искарва потребителите от

H

He3aBuCuM

Registered
Може ли някак си да се направи да излиза кой от phpbb2 форума ми е онлайн като потребителско име ,а не като айпи?
http://web-tourist.net/login/login/view.php?st=1775
За този урок говоря...
Ще може ли да се направи?
 
Код: 
<script language="JavaScript" src="overlib.js"></script>
<?
define('IN_PHPBB', true);
$phpbb_root_path = '';
include($phpbb_root_path . 'extension.inc');
include($phpbb_root_path . 'common.'.$phpEx);
define('SHOW_ONLINE', true);
$logged_visible_online = 0;
$logged_hidden_online = 0;
$guests_online = 0;
$online_userlist = '';
$l_online_users = '';
$userdata = session_pagestart($user_ip, PAGE_VIEWONLINE);
init_userprefs($userdata);

if (defined('SHOW_ONLINE'))
{

$user_forum_sql = ( !empty($forum_id) ) ? "AND s.session_page = " . intval($forum_id) : '';
$sql = "SELECT u.username, u.user_id, u.user_allow_viewonline, u.user_level, s.session_logged_in, s.session_ip
FROM ".USERS_TABLE." u, ".SESSIONS_TABLE." s
WHERE u.user_id = s.session_user_id
AND s.session_time >= ".( time() - 300 ) . "
$user_forum_sql
ORDER BY u.username ASC, s.session_ip ASC";
if( !($result = $db->sql_query($sql)) )
{
message_die(GENERAL_ERROR, 'Could not obtain user/online information', '', __LINE__, __FILE__, $sql);
}

$userlist_ary = array();
$userlist_visible = array();

$prev_user_id = 0;
$prev_user_ip = $prev_session_ip = '';

while( $row = $db->sql_fetchrow($result) )
{

// User is logged in and therefor not a guest
if ( $row['session_logged_in'] )
{
// Skip multiple sessions for one user
if ( $row['user_id'] != $prev_user_id )
{

$user_online_link = $row['username'] ;
$logged_visible_online++;
$online_userlist .= ( $online_userlist != '' ) ? ', ' . $user_online_link : $user_online_link;

}

$prev_user_id = $row['user_id'];
}
else
{
// Skip multiple sessions for one user
if ( $row['session_ip'] != $prev_session_ip )
{
$guests_online++;
}
}

$prev_session_ip = $row['session_ip'];
}
$db->sql_freeresult($result);


$total_online_users = $logged_visible_online + $logged_hidden_online + $guests_online;

$l_online_users =$total_online_users;

}
if($guests_online == 0){
$guests_online = '';
}
else if($guests_online == 1){
$gosta = ' + '.$lang['Guest_user_total'];
}
else {
$gosta = ' + '.$lang['Guest_users_total'];
}
$obshtogosta = sprintf($gosta, $guests_online);
echo ("Онлайн : <span onmouseover=\"return overlib('$online_userlist$obshtogosta');\" onmouseout=\"return nd();\" ><b>".$l_online_users."</b></span>\n");
?>
overlib.js => http://web-tourist.net/forum/overlib.js
 
Код: 
Warning: include(extension.inc) [function.include]: failed to open stream: No such file or directory in C:\xampp\htdocs\index.php on line 339

Warning: include() [function.include]: Failed opening 'extension.inc' for inclusion (include_path='.;C:\xampp\php\pear\') in C:\xampp\htdocs\index.php on line 339

Warning: include(common.php) [function.include]: failed to open stream: No such file or directory in C:\xampp\htdocs\index.php on line 340

Warning: include() [function.include]: Failed opening 'common.php' for inclusion (include_path='.;C:\xampp\php\pear\') in C:\xampp\htdocs\index.php on line 340

Fatal error: Call to a member function sql_query() on a non-object in C:\xampp\htdocs\forum\includes\sessions.php on line 313
....
 
Пробвай с този.При мен работи.
Код: 
<?
define('IN_PHPBB', true);
$phpbb_root_path ='forum/';
include($phpbb_root_path . 'config.php');
include($phpbb_root_path . 'extension.inc');
include($phpbb_root_path . 'common.'.$phpEx);
define('SHOW_ONLINE', true);
$logged_visible_online = 0;
$logged_hidden_online = 0;
$guests_online = 0;
$online_userlist = '';
$l_online_users = '';
$userdata = session_pagestart($user_ip, PAGE_VIEWONLINE);
init_userprefs($userdata);

if (defined('SHOW_ONLINE'))
{

   $user_forum_sql = ( !empty($forum_id) ) ? "AND s.session_page = " . intval($forum_id) : '';
   $sql = "SELECT u.username, u.user_id, u.user_allow_viewonline, u.user_level, s.session_logged_in, s.session_ip
      FROM ".USERS_TABLE." u, ".SESSIONS_TABLE." s
      WHERE u.user_id = s.session_user_id
         AND s.session_time >= ".( time() - 300 ) . "
         $user_forum_sql
      ORDER BY u.username ASC, s.session_ip ASC";
   if( !($result = $db->sql_query($sql)) )
   {
      message_die(GENERAL_ERROR, 'Could not obtain user/online information', '', __LINE__, __FILE__, $sql);
   }

   $userlist_ary = array();
   $userlist_visible = array();

   $prev_user_id = 0;
   $prev_user_ip = $prev_session_ip = '';

   while( $row = $db->sql_fetchrow($result) )
   {
   
      // User is logged in and therefor not a guest
      if ( $row['session_logged_in'] )
      {
         // Skip multiple sessions for one user
         if ( $row['user_id'] != $prev_user_id )
         {
                  
               $user_online_link = $row['username'] ;
               $logged_visible_online++;
               $online_userlist .= ( $online_userlist != '' ) ? ', ' . $user_online_link : $user_online_link;
            
         }

         $prev_user_id = $row['user_id'];
      }
      else
      {
         // Skip multiple sessions for one user
         if ( $row['session_ip'] != $prev_session_ip )
         {
            $guests_online++;
         }
      }

      $prev_session_ip = $row['session_ip'];
   }
   $db->sql_freeresult($result);

   
   $total_online_users = $logged_visible_online + $logged_hidden_online + $guests_online;

   $l_online_users =$total_online_users;

}
if($guests_online == 0){
$guests_online = '';
}
else if($guests_online == 1){
$gosta = ' + '.$lang['Guest_user_total'];
}
else {
$gosta = ' + '.$lang['Guest_users_total'];
}
$obshtogosta = sprintf($gosta, $guests_online);
echo ("На линия: <span onmouseover=\"return overlib('$online_userlist$obshtogosta');\" onmouseout=\"return nd();\" ><b>".$l_online_users."</b></span>\n");
?>
 
Трябва да си влезнал или регистриран, за да отговориш тук.

Back
Горе