Колко дни остават до дадена дата
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Fakeheal
Super Moderator
PHP:
//FUNCTION FOR TIME LEFT
function time_left($integer)
{
$seconds=$integer;
if ($seconds/60 >=1)
{
$minutes=floor($seconds/60);
if ($minutes/60 >= 1)
{ # Hours
$hours=floor($minutes/60);
if ($hours/24 >= 1)
{ #days
$days=floor($hours/24);
if ($days/7 >=1)
{ #weeks
$weeks=floor($days/7);
if ($weeks>=2) $return="$weeks Weeks";
else $return="$weeks Week";
} #end of weeks
$days=$days-(floor($days/7))*7;
if ($weeks>=1 && $days >=1) $return="$return, ";
if ($days >=2) $return="$return $days days";
if ($days ==1) $return="$return $days day";
} #end of days
$hours=$hours-(floor($hours/24))*24;
if ($days>=1 && $hours >=1) $return="$return, ";
if ($hours >=2) $return="$return $hours hours";
if ($hours ==1) $return="$return $hours hour";
} #end of Hours
$minutes=$minutes-(floor($minutes/60))*60;
if ($hours>=1 && $minutes >=1) $return="$return, ";
if ($minutes >=2) $return="$return $minutes minutes";
if ($minutes ==1) $return="$return $minutes minute";
} #end of minutes
$seconds=$integer-(floor($integer/60))*60;
if ($minutes>=1 && $seconds >=1) $return="$return, ";
if ($seconds >=2) $return="$return $seconds seconds";
if ($seconds ==1) $return="$return $seconds second";
$return="$return.";
return $return;
}
/* Returns a string of the amount of time the integer (in seconds) refers
to.
$timeleft=time_left(86400);
$timeleft='1 day'.
Will not return anything higher than weeks. False if $integer=0 or fails.
*/Може и аз нещо да бъркам
PHP:
function time_left($integer)
{
$seconds=$integer;
if ($seconds/60 >=1)
{
$minutes=floor($seconds/60);
if ($minutes/60 >= 1)
{ # Hours
$hours=floor($minutes/60);
if ($hours/24 >= 1)
{ #days
$days=floor($hours/24);
if ($days/7 >=1)
{ #weeks
$weeks=floor($days/7);
if ($weeks>=2) $return="$weeks Weeks";
else $return="$weeks Week";
} #end of weeks
$days=$days-(floor($days/7))*7;
if ($weeks>=1 && $days >=1) $return="$return, ";
if ($days >=2) $return="$return $days days";
if ($days ==1) $return="$return $days day";
} #end of days
$hours=$hours-(floor($hours/24))*24;
if ($days>=1 && $hours >=1) $return="$return, ";
if ($hours >=2) $return="$return $hours hours";
if ($hours ==1) $return="$return $hours hour";
} #end of Hours
$minutes=$minutes-(floor($minutes/60))*60;
if ($hours>=1 && $minutes >=1) $return="$return, ";
if ($minutes >=2) $return="$return $minutes minutes";
if ($minutes ==1) $return="$return $minutes minute";
} #end of minutes
$seconds=$integer-(floor($integer/60))*60;
if ($minutes>=1 && $seconds >=1) $return="$return, ";
if ($seconds >=2) $return="$return $seconds seconds";
if ($seconds ==1) $return="$return $seconds second";
$return="$return.";
return $return;
}
$new = mktime(0,0,0, date("m"), date("d", 1314285312)+4, date("Y"));
echo time_left($new);защо просто не направим сметката по timestamp:
PHP:
<?php
echo "Days:".DaysLeft('2011-08-20');
function DaysLeft( $DateString, $Period='d' ) {
date_default_timezone_set('Europe/Sofia');
$times = array('i'=>60 /*min*/,'h'=>60*60 /*hour*/,'d'=>60*60*24 /*day*/,'w'=>60*60*24*7 /*week*/);
return (strtotime($DateString)>0) ? ceil( (time()-strtotime($DateString))/$times[$Period])-1 : false;
}
?>
Код:
$time_left= 100000; //колко време остава в time формат
$days = floor($time_left / 86400);
$time_left = $time_left - $days * 86400;
$hours = floor($time_left / 3600);
$time_left = $time_left - $hours * 3600;
$minutes = floor($time_left / 60);
$seconds = $time_left - $minutes * 60;
echo "остават ".$days."дена ".$hours.":".$minutes;Може да се добави и секунди...
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