Обратно броене с Java Script

Gamerz

Registered
Някой може ли да ми даде някакъв съвсем елементарен брояч в който като въведа някаква дата и час да ми отброява колко остава. Най-елементарното ми трябва.
 
http://www.web-tourist.net/login/login/view.php?st=1522
http://www.web-tourist.net/forum/viewtopic.php?t=92546
http://www.web-student.com/forum/viewtopic.php?t=84331
http://bg-bg.facebook.com/note.php?note_id=184077257090
 
Код:
<div id="html1" style="position:absolute; overflow:hidden; left:0px; top:0px; width:730px; height:71px; z-index:0">
<form name="count">
<input type="text" size="75" name="count2">
</form>
</div>

<script>


var before="Нещоси!"
var current="Това е текста който ще ви покаже след отброяването!"
var montharray=new Array("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec")

function countdown(yr,m,d){
theyear=yr;themonth=m;theday=d
var today=new Date()
var todayy=today.getYear()
if (todayy < 1000)
todayy+=1900
var todaym=today.getMonth()
var todayd=today.getDate()
var todayh=today.getHours()
var todaymin=today.getMinutes()
var todaysec=today.getSeconds()
var todaystring=montharray[todaym]+" "+todayd+", "+todayy+" "+todayh+":"+todaymin+":"+todaysec
futurestring=montharray[m-1]+" "+d+", "+yr
dd=Date.parse(futurestring)-Date.parse(todaystring)
dday=Math.floor(dd/(60*60*1000*24)*1)
dhour=Math.floor((dd%(60*60*1000*24))/(60*60*1000)*1)
dmin=Math.floor(((dd%(60*60*1000*24))%(60*60*1000))/(60*1000)*1)
dsec=Math.floor((((dd%(60*60*1000*24))%(60*60*1000))%(60*1000))/1000*1)
if(dday==0&&dhour==0&&dmin==0&&dsec==1){
document.forms.count.count2.value=current
return
}
else
document.forms.count.count2.value="Остават "+dday+ " дни, "+dhour+" часа, "+dmin+" минути, and "+dsec+" секунди остават до "+before
setTimeout("countdown(theyear,themonth,theday)",1000)
}
countdown(2011,05,08)
</script>

http://www.web-tourist.net/login/login/view.php?st=1522
 

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