Онклик

[mitko876]

echo'<input type="text" value="' . $news[text] . '" id="bg"><input type="button" onclick="showHinttt(\'' . $news[id] . ', document.getElementById(\'bg\').value\');" value="GO">';

Защо ей това кодче все не иска за се изпълнява

 

[adrian]

Дай си и JS кода.

 

[mitko876]

var xmlHttp 

function showHinttt(str, str2) 
{ 
if (str.length <= 1 || str2.length <= 1) 
{ 
document.getElementById("loading").innerHTML=""
return 
} 
xmlHttp=GetXmlHttpObject() 
if (xmlHttp==null) 
{ 
alert ("Browser does not support HTTP Request") 
return 
}

var load = document.getElementById("lloading") 
if(load!=undefined) load.innerHTML="Loading..."
 
var url="newsa.php" 
url=url+"?d="+str  
url=url+"&c="+str2 
url=url+"&sid="+Math.random() 
xmlHttp.onreadystatechange=stateChanged 
xmlHttp.open("GET",url,true) 
xmlHttp.send(null) 
} 

function stateChanged() 
{ 
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") 
{ 
document.getElementById("loading").innerHTML=xmlHttp.responseText 
} 
} 

function GetXmlHttpObject() 
{ 
var xmlHttp=null; 
try 
{ 
// Firefox, Opera 8.0+, Safari 
xmlHttp=new XMLHttpRequest(); 
} 
catch (e) 
{ 
// Internet Explorer 
try 
{ 
xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); 
} 
catch (e) 
{ 
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); 
} 
} 
return xmlHttp; 
}

ето AJAX е

 

[bafitu]

echo'<input type="text" value="' . $news[text] . '" id="bg"><input type="button" onclick="showHinttt(\'' . $news[id] . '\', document.getElementById(\'bg\').value);" value="GO">';

 

[mitko876]

не