Здравейте! Пиша един скрипт, но сега имам един проблем. При този код:
И ми дава тази грешка:
Код:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
</head>
<body>
<div id="container">
<p>My view has been loaded</p>
<?php foreach($rows as $r) : ?>
<h1><?php echo $r->title; ?></h1>
<div><?php echo $r->contents; ?></div>
<div><?php echo $r->author; ?></div>
<?php endforeach; ?>
</div>
</body>
</html>
Код:
My view has been loaded
A PHP Error was encountered
Severity: Warning
Message: Invalid argument supplied for foreach()
Filename: views/home.php
Line Number: 13