Проблем с PHP скрипт

[bganonymous]

Здравейте! Имам проблем с този PHP скрипт за изтриване на потребител от приятели. Просто не работи.

<?php
$get_id = (int) $_GET['id'];
$from_user = $urow['username'];
$from_id = $urow['id'];
if (!isset($get_id) OR !is_numeric($get_id) OR $get_id < 1) { header("Location: index.php"); }

$delete_friend = mysql_query("SELECT * FROM `friends` WHERE from_user = '$from_user' AND from_id = '$from_id' AND to_id = '$get_id'");

if (mysql_num_rows($delete_friend) == 0) { echo "Има грешка!"; }

else {

mysql_query("DELETE FROM `friends` WHERE `from_user` = '$from_user', `from_id` = '$from_id', `to_id` = '$get_id'");

header("Location: friends.php");

}

?>

 

[swlight]

<?php
$get_id = (int) $_GET['id'];
$from_user = $urow['username'];
$from_id = $urow['id'];
if (!isset($get_id) OR !is_numeric($get_id) OR $get_id < 1) { header("Location: index.php"); }

$delete_friend = mysql_query("SELECT * FROM `friends` WHERE from_user = '$from_user' AND from_id = '$from_id' AND to_id = '$get_id'");

if (mysql_num_rows($delete_friend) == 0) { echo "Има грешка!"; }

else {

mysql_query("DELETE FROM `friends` WHERE `from_user` = '$from_user' AND `from_id` = '$from_id' AND `to_id` = '$get_id'");

header("Location: friends.php");

}

?>

 

[vinsbg]

Просто не работи, какво означава?

 

[eLite]

mysql_query("DELETE FROM `friends` WHERE `from_user` = '$from_user' AND `from_id` = '$from_id' AND `to_id` = '$get_id'");

 

[bganonymous]

mysql_query("DELETE FROM `friends` WHERE `from_user` = '$from_user' AND `from_id` = '$from_id' AND `to_id` = '$get_id'");

Warning: mysql_query() expects parameter 1 to be string, resource given in...

 

[djman]

bganonymous, сигурен ли си, че дава грешка на този ред?