Проверка за level?

[tedobedo]

Имам следната логин системата:

<?php
session_start();

 include 'includes/config.php';
 $username = trim(addslashes(htmlspecialchars($_POST['username'])));
 $password = trim(addslashes(htmlspecialchars($_POST['password'])));
if($_SERVER['REQUEST_METHOD'] != "POST")
{
    header('Location: index.php');
}
else
{
 if(isset($username) && isset($password))
     {
     $newPass = md5("asd".$password."13");
     $q = mysql_query("SELECT username, password FROM users WHERE username='$username' AND password='$newPass' LIMIT 1") or die(mysql_error());
        if(mysql_num_rows($q) == 1)
            {
            $user = mysql_fetch_assoc($q);
            $_SESSION['username'] = $user['username'];
            $username = $_SESSION['username'];
            $select = mysql_query("SELECT * FROM users WHERE username='$username'");
             header('Location: index.php');
            }
            else
            {
                 header('Location: index.php');
                 $_SESSION['error'] = "Грешно име или парола!";
            }
     }
}
 ?>

Искам ако потребителя има level 3 да му изведе някакъв текст. Редът ми се казва level, а колоната users

 

[smoke]

ЕТО:

$select_user = mysql_query("SELECT * FROM `table_user` WHERE `username` = '".$_SESSION['username']; ."' ") or die (mysql_error());
$row = mysql_fetch_array($select_user);

if($row['level'] == 3) {

echo "neshto";

}