Правя един сайт в който ще има тестове, та въпроса ми е как да направя така че сами отговори да се разбъркват ?
PHP:
<?php
$select = mysql_query("SELECT * FROM $dbname.vupros ORDER BY id")or die(mysql_error());
$num = mysql_num_rows($select);
echo "$number ";
for ($i=0;$i<$num;$i++) {
$id = mysql_result($select, $i, "id");
$name = mysql_result($select, $i, "vupros");
$veren = mysql_result($select, $i, "veren");
$otg1 = mysql_result($select, $i, "otg1");
$otg2 = mysql_result($select, $i, "otg2");
$otg3 = mysql_result($select, $i, "otg3");
$otg4 = mysql_result($select, $i, "otg4");
$otg5 = mysql_result($select, $i, "otg5");
$otg6 = mysql_result($select, $i, "otg6");
$otg7 = mysql_result($select, $i, "otg7");
echo '<table>';
echo '<tr><td>'.$id.':<b>'.$name.'</b></td></tr>';
echo '
<tr><td><input type="radio" name="a1" value="'.$veren.'" />: '.$veren.'</td></tr>
<tr><td><input type="radio" name="a1" value="'.$otg1.'" />: '.$otg1.'</td></tr>
<tr><td><input type="radio" name="a1" value="'.$otg2.'" />: '.$otg2.'</td></tr>';
if(!empty($otg3)) { echo '<tr><td><input type="radio" name="a1" value="'.$otg3.'" />: '.$otg3.'</td></tr>'; }
if(!empty($otg4)) { echo '<tr><td><input type="radio" name="a1" value="'.$otg4.'" />: '.$otg4.'</td></tr>'; }
if(!empty($otg5)) { echo '<tr><td><input type="radio" name="a1" value="'.$otg5.'" />: '.$otg5.'</td></tr>';}
if(!empty($otg6)) { echo '<tr><td><input type="radio" name="a1" value="'.$otg6.'" />: '.$otg6.'</td></tr>'; }
if(!empty($otg7)) { echo '<tr><td><input type="radio" name="a1" value="'.$otg7.'" />: '.$otg7.'</td></tr>'; }
echo '<br /><hr></table>';
}
?>