Хоризонтално подреждане на клипове

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Здравейте, значи искам да направя така,че да ми излизат последни 4 клипа,само че да излизат хоризонтално,а те вмомента излизат вертикално.Имам 2 файла,единият е php,а другият е html.

ето php файла

Код:
<?php

$_language->read_module('movies');

	$ergebnis=safe_query("SELECT * FROM ".PREFIX."mymovies ORDER BY movieID DESC LIMIT 0,5");
	echo'<table cellpadding="0" cellspaceing="0" width="100%">';
		while($ds = mysql_fetch_array($ergebnis)){
		
			$preview = $ds['movielink'];
			$id		 = $ds['movieID'];
			$uploader= getnickname($ds['uploader']);
			$name	 = $ds['moviename'];
			$rating=$ds['rating'];
			$views=$ds['viewed'];

	eval ("\$sc_movies = \"".gettemplate("sc_movies")."\";");
	echo $sc_movies;
		}
	echo'</table>';
?>

а ето и html

Код:
<table>
<tr>
	<td width="174" align="left"><a href="index.php?site=movies&action=show&movieID=$id"><img src="http://i1.ytimg.com/vi/$preview/default.jpg" width="120" height="80" alt="Vorschau" style="border: 1px solid #d7d7d7; padding: 2px; text-decoration: none; background: #FFF;" /></a></td>
</tr>
<tr>
	<td width="174" height="10"><span class="boxtext" style="color:#434343"><a href="index.php?site=movies&action=show&movieID=$id">$name</a></span></td>
</tr>
<tr>

	<td width="174" height="10"><span class="boxtext" style="color:#434343">Uploader: $poster</span></td>
</tr>
<tr>
	<td width="174" height="10"><span class="boxtext" style="color:#434343">%rating% $rating</span></td>
</tr>
<tr>
	<td width="174" height="10"><span class="boxtext" style="color:#434343">%views% $views</span></td>
</tr>
</table>
 
Редактирай html кода с този
Код:
<table style="float:left;">
<tr>
   <td width="174" align="left"><a href="index.php?site=movies&action=show&movieID=$id"><img src="http://i1.ytimg.com/vi/$preview/default.jpg" width="120" height="80" alt="Vorschau" style="border: 1px solid #d7d7d7; padding: 2px; text-decoration: none; background: #FFF;" /></a></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343"><a href="index.php?site=movies&action=show&movieID=$id">$name</a></span></td>
</tr>
<tr>

   <td width="174" height="10"><span class="boxtext" style="color:#434343">Uploader: $poster</span></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343">%rating% $rating</span></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343">%views% $views</span></td>
</tr>
</table>
 
Ами има ли как да го направя да не излиза цялото име ,т.е. заглавието.защото се разминават ако е малко по-дълго имато.Иначе това стана.
 
Тук където виждаш отнчало 0, 10 на мястото на 10 слагаш до колко знака искаш да ти извежда от името :)
Код:
<?
$name=substr($name, 0, 10);
?>

<table style="float:left;">
<tr>
   <td width="174" align="left"><a href="index.php?site=movies&action=show&movieID=$id"><img src="http://i1.ytimg.com/vi/$preview/default.jpg" width="120" height="80" alt="Vorschau" style="border: 1px solid #d7d7d7; padding: 2px; text-decoration: none; background: #FFF;" /></a></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343"><a href="index.php?site=movies&action=show&movieID=$id">$name</a></span></td>
</tr>
<tr>

   <td width="174" height="10"><span class="boxtext" style="color:#434343">Uploader: $poster</span></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343">%rating% $rating</span></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343">%views% $views</span></td>
</tr>
</table>
 
php кода

Там където е 10 пак така, слагаш до колко знака искаш да ти показва
Код:
<?php

$_language->read_module('movies');

   $ergebnis=safe_query("SELECT * FROM ".PREFIX."mymovies ORDER BY movieID DESC LIMIT 0,5");
   echo'<table cellpadding="0" cellspaceing="0" width="100%">';
      while($ds = mysql_fetch_array($ergebnis)){
      
         $preview = $ds['movielink'];
         $id       = $ds['movieID'];
         $uploader= getnickname($ds['uploader']);
         $name    = substr($ds['moviename'], 0, 10);
         $rating=$ds['rating'];
         $views=$ds['viewed'];

   eval ("\$sc_movies = \"".gettemplate("sc_movies")."\";");
   echo $sc_movies;
      }
   echo'</table>';
?>


HTML кода

Код:
<table style="float:left;">
<tr>
   <td width="174" align="left"><a href="index.php?site=movies&action=show&movieID=$id"><img src="http://i1.ytimg.com/vi/$preview/default.jpg" width="120" height="80" alt="Vorschau" style="border: 1px solid #d7d7d7; padding: 2px; text-decoration: none; background: #FFF;" /></a></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343"><a href="index.php?site=movies&action=show&movieID=$id">$name</a></span></td>
</tr>
<tr>

   <td width="174" height="10"><span class="boxtext" style="color:#434343">Uploader: $poster</span></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343">%rating% $rating</span></td>
</tr>
<tr>
   <td width="174" height="10"><span class="boxtext" style="color:#434343">%views% $views</span></td>
</tr>
</table>
 

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