Значи дава ми тази грешка:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /var/www/clients/client253/web733/web/csplayers/forum.php on line 12
то го и прословутия код:
а 12 ред е:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /var/www/clients/client253/web733/web/csplayers/forum.php on line 12
то го и прословутия код:
Код:
<?php
$connection = @mysql_connect($host, $dbuser, $dbpass) or die ("MySQL Fatal Error");
@mysql_select_db($db_name);
$table_preffix = ""; //Префикс на таблиците
$table_topics = "topics"; //Таблицата
$show_topics = 5; //Колко теми да показва
$forum_path = "forum/"; //Папката където се намира форума
$table_topics = $table_preffix."topics";
$query = mysql_query("SELECT * FROM $table_topics ORDER BY tid DESC LIMIT 0, $show_topics");
while($row = mysql_fetch_array($query)) {
$title = $row[title];
$address = $row[tid];
$address = $forum_path."index.php?showtopic=".$address;
$author = $row[starter_name];
$posts = $row[posts];
echo '
</tr>
<tr>
<td width="40%" class="border2">
<a href="'.$address.'" class="other">' . substr($title, 0, 55) . '...</a></td>
<td width="20%" class="border2">'.$posts.'</td>
<td width="40%" class="border2">'.$author.'</td>
</tr>';
}
?>
а 12 ред е:
Код:
while($row = mysql_fetch_array($query)) {