Здравейте може ли малко да ми помогнете искам резултатите от финкцията да излизат в таблица един под дръг за определеното поле , направих не6то но то изобщо не е това което искам
<?php
$select = $_POST["base"];
$text = $_POST["mes"];
//echo $select;
//echo $text;
$host="localhost";
$user="root";
$password="";
$db="bgsites";
$connect=mysql_connect("localhost","root","");
if (!$connect) { echo("ERROR: " . mysql_error() . "\n"); }
mysql_select_db($db) or die ("no select DB");
$query="SELECT url,text,phone,email FROM urls where date_created='$text' and pr='$select' ";
//echo $query;
//exit;
if (!$query) {echo("ERROR:". mysql_error()."\n");}
$result= mysql_query($query);
while ($row = mysql_fetch_array($result))
{
echo"<table border=3 width=800 height=50><tr><td><b>"."Domain: ".$row ["url"]."</tr></td></table><br>";
echo"Information: ".$row["text"]."<br>";
echo "Phone: ".$row["phone"]."<br>";
echo "Email: ".$row["email"]."<br>";
}
mysql_close( );
?>
мерси предварително
<?php
$select = $_POST["base"];
$text = $_POST["mes"];
//echo $select;
//echo $text;
$host="localhost";
$user="root";
$password="";
$db="bgsites";
$connect=mysql_connect("localhost","root","");
if (!$connect) { echo("ERROR: " . mysql_error() . "\n"); }
mysql_select_db($db) or die ("no select DB");
$query="SELECT url,text,phone,email FROM urls where date_created='$text' and pr='$select' ";
//echo $query;
//exit;
if (!$query) {echo("ERROR:". mysql_error()."\n");}
$result= mysql_query($query);
while ($row = mysql_fetch_array($result))
{
echo"<table border=3 width=800 height=50><tr><td><b>"."Domain: ".$row ["url"]."</tr></td></table><br>";
echo"Information: ".$row["text"]."<br>";
echo "Phone: ".$row["phone"]."<br>";
echo "Email: ".$row["email"]."<br>";
}
mysql_close( );
?>
мерси предварително