galabin123
Registered
Код:
$lv = $row4['lv'] + 1;
$у = $row4['id'];
$sql5 = "UPDATE `gigants` SET `lv`='$lv' WHERE `u`='$y'";
$res5 = mysql_query($sql5) or die(mysql_error());
echo "Успешно дигна 2-ри левъл!";
не разбирам къде е грешката
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '` WHERE `username`='d1vak'' at line 1